Question Q: For a basic computer that is currently running in its timing TO of execution for an instruction that is located in memory location 366. The content of AC is (212) and the content of memory locations are as follow: [memory location: content): (365:9473), (366:7010), (367:5431), [368:4620], [431:1A23], [620:C80D]. Answer the following questions that examine the contents of PC, AR, AC, DR and IR after the end of execution for the next instruction. ((Note: all numbers are in Hexadecimal The content of IR after the end of execution for the next instruction is * 4620 O 9473 5431 None of the choices 7010 O