Question Stem Consider the lines L1 and L2 defined by Lx2+y-1=0 and L2: x2-y+1=0 For a fixed constant , let C be the locus of a point P such that the product of the distance of P from L, and the distance of P from L is 22. The line y = 2x + 1 meets C at two points R and S, where the distance between R and S is 270. Let the perpendicular bisector of RS meet C at two distinct points R' and S'. Let D be the square of the distance between R' and S' 9. The value of 1 is Sol. 9 Locus C => (x2+y-1)(x2-y+1) =22 3 2x-(y-1)=+32? for intersection with y = 2x + 1 2x-(2x)=322 -2x=-322 (taking-ve sign)