Question: The average score in a statewide aptitude exam for all FCAT students in the Florida

state follows a normal distribution with a mean of 75. A random sample of 36 students are

selected and the sample mean score of these 36 students is obtained as 85 with a standard

deviation of 20 points. Use 5% level of significance do we have sufficient evidence to prove that

the students are highly skilled in their mathematical abilities than the claimed average?

Null Hypothesis,H0:

.

{Fill the first blank with correct option which can be either = or < or > or <>. Fill the second blank with the hypothesized value, i.e., claim value}

Alternate Hypothesis,H1:

.

{Fill the first blank with the correct option which can be either = or < or > or <> for a two tail test. Fill the second box with the hypothesized value, i.e., claim value}.

This is atail test.

{Fill in the blank with either left or right or two}.

Sigma is;

{Based on the details given in the question, fill the blank with either known or unknown}

We have the sample size, n30.

{Fill the blankwith either = or < or > or <>}

We use- distribution.

{Fill the blank with z or t}

Critical value is=.

{Fill the first blank with z or t. Fill the second blank with the critical value rounded to four decimals; to report a critical value for two tail test just enter the positive value}

Test Statistic value is=.

{Fill the first blank with z or t. Fill the second blank with the computed test statistic value rounded to TWO decimals};

p-value =.

{Fill the blank with the computed p-value; Note that for a t-distribution, p-value will be in interval format. In that case, enter the answer as 0.005

Decision: p-value isthe level of significance,

{Fill the blank with < or > or = or <>}

At the given level of significance, we haveevidence to reject theH0

{Fill the blank with sufficient or insufficient}.

We conclude that the test is.

{Fill the blank with significant or insignificant}