Question: Question: The simply supported beam is subjected to distributed forces as shown in below figure: We want to simply the above problem by taking the

Question: The simply supported beam is subjected to distributed forces as shown in below figure:
We want to simply the above problem by taking the integration of the distributed forces and reducing into the equivalent force loading as:
The calculation of the acting force due to distributed loading w(x) can be formulated as a function:
F1(x)=0xw(t)dt=0x50e20t(t2-0.15)dt,FT=F1(0.3)
Using the above definition, the distance "xf" can also be formulated as:
xf=t.w(t)dxw(t)dx=F2(x)F1(x)=0x50e20t(t2-0.15)dt=0x50e20t(t2-0.15)dt=0xt50e201(t2-0.15)dt,F20.3F1(0.3)
Find the force "FT" and the position "xf" of the equivalent system using Taylor series expansion for F1(x) And F2(x) expanded at point "0". Write all your calculations in detail (if you use a computer program, attach the derivations to the submission, submission must be a single file) at each iteration. Starting from the TS0 expansion, continue your iteration until approximate fractional error satisfies the s=0.1 value for integral calculations of F1(x) and F2(x). Show your final "xf" and "FT" value on the equivalent system.
Question: The simply supported beam is subjected

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