In comparing the length of the tensile strength of two kinds of structural steel, an experiment...

  

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In comparing the length of the tensile strength of two kinds of structural steel, an experiment yielded the following results: M=13, n=16. The sample variance of the first sample was 19.2 and for the second sample was 3.5. Assuming the measurements x=5 constitute an independent sample from normal population. Using H₁:o*H.:o hypothesis that hypothesis test. Calculate H₂:0=0 (i) Let X be normal random variable with mean Hand variance 4. For the following H₁:μ=1 VsH₁: p=2 Vs P (type I error) P (type II error) . Suppose we reject H Test the null when [5 marks] X≥3 [3 marks] [3 marks] In comparing the length of the tensile strength of two kinds of structural steel, an experiment yielded the following results: M=13, n=16. The sample variance of the first sample was 19.2 and for the second sample was 3.5. Assuming the measurements x=5 constitute an independent sample from normal population. Using H₁:o*H.:o hypothesis that hypothesis test. Calculate H₂:0=0 (i) Let X be normal random variable with mean Hand variance 4. For the following H₁:μ=1 VsH₁: p=2 Vs P (type I error) P (type II error) . Suppose we reject H Test the null when [5 marks] X≥3 [3 marks] [3 marks]

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answer i P type I error P X 3 H 1 1 P X 3 H 1 1 3 00013 ii P type II error P X 3 H 2 3 09987 Explana... View the full answer