Question: In comparing the length of the tensile strength of two kinds of structural steel, an experiment yielded the following results: M=13, n=16. The sample
In comparing the length of the tensile strength of two kinds of structural steel, an experiment yielded the following results: M=13, n=16. The sample variance of the first sample was 19.2 and for the second sample was 3.5. Assuming the measurements x=5 constitute an independent sample from normal population. Using H:o*H.:o hypothesis that hypothesis test. Calculate H:0=0 (i) Let X be normal random variable with mean Hand variance 4. For the following H:=1 VsH: p=2 Vs P (type I error) P (type II error) . Suppose we reject H Test the null when [5 marks] X3 [3 marks] [3 marks]
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answer i P type I error P X 3 H 1 1 P X 3 H 1 1 3 00013 ii P type II error P X 3 H 2 3 09987 Explana... View full answer
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