Question: Question#3 Given the following 2-byte short-jump instruction ( 6 points): 2020H:1200HCS:IPJNZLocationInstruction75XHMachineCode a) Given ZF=0, What's the value of the XX that makes the code enters

$Question\#3 Given the following 2-byte short-jump instruction ( 6 points): 2020H:1200HCS:IPJNZLocationInstruction75XHMachineCode$

Question\#3 Given the following 2-byte short-jump instruction ( 6 points): 2020H:1200HCS:IPJNZLocationInstruction75XHMachineCode a) Given ZF=0, What's the value of the XX that makes the code enters in an infinite-loop (stuck executing the JNZ Location instruction): b) What's the value of XX that keeps the execution of the code sequentially regardless the value of the ZF ? c) If the value of XX is 32H, what makes the code executes the instruction located at address 2020H:1202H directly after the JNZ location instruction: d) If the JNZ instruction transfers the execution of the code to physical address 21445H, then the value of XX is

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