Question: R - 1 4 . 7 Consider the unsorted sequence implementation of the priority queue Q used in Dijkstra's algorithm. In this case, why is

R-14.7 Consider the unsorted sequence implementation of the priority queue Q used in Dijkstra's algorithm. In this case, why is the best-case running time of Dijkstra's algorithm (n2) on an n-vertex graph?
Hint: Consider the size of Q each time the minimum element is extracted.
R - 1 4 . 7 Consider the unsorted sequence

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