Question: r 2 = r 3 * 1 0 5 can be solved by following? RSB r 1 , r 3 , r 3 , LSL

r2= r3*105 can be solved by following?
RSB r1, r3, r3, LSL #3 and RSB r2, r1, r1, LSL #4
RSB r1, r3, r3, LSL #4 and RSB r2, r1, r1, LSL #3
RSB r2, r2, r3, LSL #4 and RSB r3, r2, r3, LSL #3
RSB r3, r2, r2, LSL #4 and RSB r2, r3, r3, LSL #3
In mode 3 of serial communication which timer controls the baud rate?
T1 in mode 2
T0 in mode 1
T1 in mode 1
T0 in mode 0
Find the time delay in secs (Excluding overhead due to instructions in the loop):
MOV TMOD, #10H
MOV R3, #200
AGAIN: MOV TL1, #08H
MOV TH1, #01H
SETB TR1
BACK: JNB TF1, BACK
CLR TR1
CLR TF1
DJNZ R3, AGAIN
14.164024msecs
1.4164024secs
1416.4024\mu secs
None of the above
How the status of the carry, auxiliary carry and parity flags affected if we write the instruction?
MOV A, #9C
ADD A, #64H
CY=0, AC=1, P=0
CY=0, AC=0, P=0
CY=1, AC=1, P=0
CY=1, AC=1, P=1
Assuming 8051 crystal frequency 11.0952MHz, what values do we need to load in Timer 1 registers, if we want to have a time delay 5msecs?
TH1=238, TL1=0H
TH1= EEH, TL1=01H
TH0= EEH, TL0=0H
TH0= EEH, TL =0A
For the following piece of ALP in 8051(Not a complete code), what is the Baud rate?
Org 0030H
MAIN: MOV TMOD, #20H
MOV TH1, #FAH
MOV SCON, #50H
SETB TR1
Baud Rate =9600H
Baud Rate =4800
Baud Rate =9600
Baud Rate =4800H
Assuming 8051 crystal frequency 16MHz and following specifications determine the delay generated by Timer 0: Specifications: Timer Mode 0 is selected, TL0=62, TH0= B8H
19.93145mSec
1.993145mSecs
None of the above
19.93145\mu Secs
If SP =3FH, then at what memory location the SP is pointing to after the execution of the following command?
MOV R0, #32H
MOV R1, #3FH
MOV R3, #25H
PUSH R0
PUSH R1
PUSH 0E0H
POP R3
SP =43H
SP =41H
SP =42H
Invalid Syntax.

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