Question: R . I = x 3 0 0 1 R 2 = x 3 0 0 2 R 3 = x 3 0 0 3

R.I=x3001
R2=x3002
R3=x3003
And the memory contents:
Address x3100 contains the value x1234.
Address x3101 contains the value xABCD.
Address x3102 contains the value x0012.
The following is a list of instruction addresses and the corresponding instruction that is stored in the IR.
(Instruction Register). Calculate the final values of the registers after executing these instructions:
Assume that the program starts at x3000 and each instruction is one memory location after the previous.
Questions
You are required to:
Interpret each instruction based on the LC-3 instruction set. Complete the last column in the Table above.
Update the register values after each instruction execution.
Write down the register values and memory changes after all instructions have been processed.
Note: show all detailed steps for 2) and 3).
Hints
Pay attention to the initial values of the registers.
Remember that some instructions may change the values of the registers used by subsequent instructions.
Consider the effects of instructions like AND R1, R0, #0 which effectively clears the destination register.
The STR instruction's offset is added to the base register to determine the final address where the value is
stored.1.
 R.I=x3001 R2=x3002 R3=x3003 And the memory contents: Address x3100 contains the

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Databases Questions!