Radioactive decay is a process that follows first$-$order kinetics. The half$-$life of ${?}^{41}Ar$ is $0\mathrm{.}01256$ years; how long $($in hours$)$ would it take for the amount of ${?}^{41}$ Ar to decrease to $74\mathrm{.}97\%$ of its initial amount?

Key Concept: Half$-$life for first order reaction. $1\frac{1}{2}=\frac{0\mathrm{.}693}{k}.$

Strategy: Determine rate constant and then calculate time using integrated first order rate law.