Question: Rafa claims that if we modify the ECB mode as follows, it will become CPA secure: As before, a message is divided into blocks, so

Rafa claims that if we modify the ECB mode as follows, it will become CPA secure: As
before, a message is divided into blocks, so a message m would be m = m0\| m1\|\| mw
(where w is an integer). For each message, we generate a fresh random string r of length
n bits, and we encrypt the message as Ek(m)=(Ek(m1\| r), Ek(m2\| r),..., Ek(mw \| r)).
Is Rafas claim true? why?
Rafa claims that if we modify the ECB mode as follows, it will become CPA secure: As
before, a message is divided into blocks, so a message m would be m = m0\| m1\|\| mw
(where w is an integer). For each message, we generate a fresh random string r of length
n bits, and we encrypt the message as Ek(m)=(Ek(m1\| r), Ek(m2\| r),..., Ek(mw \| r)).
Is Rafas claim true? why?

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