Question: Read the input one line at a time and output the current line if and only if it is not a suffix of some previous

Read the input one line at a time and output the current line if and only if it is not a suffix of some previous line. For example, if the some line is "0xdeadbeef" and some subsequent line is "beef", then the subsequent line should not be output.

I my current attempt at solving this question is below but it is not efficient enough:

//package comp2402a1;

import java.io.BufferedReader;

import java.io.FileReader;

import java.io.FileWriter;

import java.io.IOException;

import java.io.InputStreamReader;

import java.io.PrintWriter;

import java.util.ArrayList;

import java.util.HashSet;

import java.util.Set;

public class Part6 {

public static void getWordSuffixes(String text, Set<String> suffixes)

{

for ( int i = 0; i <= text.length(); i++)

{

if (text.substring(text.length() - i, text.length()).length() != 0) {

suffixes.add(text.substring(text.length() - i, text.length()));

}

}

}

/**

* Your code goes here - see Part0 for an example

* @param r the reader to read from

* @param w the writer to write to

* @throws IOException

*/

public static void doIt(BufferedReader r, PrintWriter w) throws IOException {

// Your code goes here - see Part0 for an example

Set<String> suffixes = new HashSet<>();

ArrayList<String> s = new ArrayList<String>();

boolean first = true ;

for (String line = r.readLine(); line != null ; line = r.readLine()) {

if (!suffixes.contains(line) || first) {

s.add(line);

first = false ;

}

getWordSuffixes (line, suffixes);

}

for (String text : s) {

w.println(text);

}

}

/**

* The driver. Open a BufferedReader and a PrintWriter, either from System.in

* and System.out or from filenames specified on the command line, then call doIt.

* @param args

*/

public static void main(String[] args) {

try {

BufferedReader r;

PrintWriter w;

if (args.length == 0) {

r = new BufferedReader( new InputStreamReader(System. in ));

w = new PrintWriter(System. out );

} else if (args.length == 1) {

r = new BufferedReader( new FileReader(args[0]));

w = new PrintWriter(System. out );

} else {

r = new BufferedReader( new FileReader(args[0]));

w = new PrintWriter( new FileWriter(args[1]));

}

long start = System. nanoTime ();

doIt (r, w);

w.flush();

long stop = System. nanoTime ();

System. out .println("Execution time: " + 10e-10 * (stop-start));

} catch (IOException e) {

System. err .println(e);

System. exit (-1);

}

}

}


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To address the efficiency issue you are encountering in your implementation we can improve the way suffixes are handled and checked Instead of storing ... View full answer

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