The 2 tail of the sequence Y = (1,3, 5, 7,9,..., 2n 1, ...)...

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The 2 – tail of the sequence Y = (1,3, 5, 7,9,..., 2n – 1, ...) is: ) is: %3| - O Y2 = (5,7,9, ... , 2n + 3, ...) Y2 = (5, 7,9, ..., 2n, ...) O Y2 = (7,9, ..., 2n + 5,...) O Y2 = (3, 5, 7,9,... , 2n + 1,...) O Y2 = (1, 3, 5, ... , 2n – 1, ...) The 2 – tail of the sequence Y = (1,3, 5, 7,9,..., 2n – 1, ...) is: ) is: %3| - O Y2 = (5,7,9, ... , 2n + 3, ...) Y2 = (5, 7,9, ..., 2n, ...) O Y2 = (7,9, ..., 2n + 5,...) O Y2 = (3, 5, 7,9,... , 2n + 1,...) O Y2 = (1, 3, 5, ... , 2n – 1, ...)

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Given that Y 13579 3D 271 we Know that I3 X x X2 Xn X X 2 X2 Xn is a 3D ... View the full answer