Recall the following information about the $P-$value. Note that because the alternative hypothesis is $H_a$:$>1,400,$ this is an upper$-$tailed test.

$P-$value $=P(Z>z$ when $H_{0}is$ true $)$

$=$ area under the standard normal curve $to$ the right $ofz$

$=1-(z)$

Use $z=1\mathrm{.}98$ to find the probability $(1\mathrm{.}98)$ from the table of standard normal curve areas.

$\backslash$table$[[z,0\mathrm{.}00,0\mathrm{.}01,0\mathrm{.}02,0\mathrm{.}03,0\mathrm{.}04,0\mathrm{.}05,0\mathrm{.}06,0\mathrm{.}07,0\mathrm{.}08,0\mathrm{.}09$