Question: Recall the least squares problem for Ax = b. Let x denote its optimal solution, let e := b Ax be the error vector at

Recall the least squares problem for Ax = b. Let x denote its optimal solution, let e := b Ax be the error vector at optimality, and let p := Ax. Is the error vector e orthogonal to b or p or x? Show that ||e||2 equals e T b which equals b T b - p T b. This is the smallest total error E

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