Recently, Hector ran for president of the local school board. Of those who voted in the...

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Recently, Hector ran for president of the local school board. Of those who voted in the election, 75% had a high school diploma, and the other 25% did not. Hector got 60% of the vote of those with high school diplomas, while he got only 40% of the vote of those without high school diplomas. Let D denote the event that a randomly chosen voter (in the school board election) had a high school diploma and D denote the event that a randomly chosen voter did not have a high school diploma. Let H denote the event that a randomly chosen voter voted for Hector and H denote the event that a randomly chosen voter did not vote for Hector. Fill in the probabilities to complete the tree diagram below, and then answer the question that follows. Do not round any of your responses. (If necessary, consult a list of formulas.) P(H|D) = %3D P (D N H) = |[ U. P (D) = | %3D P(pn #) = %3D P(#|D) = 0.4 %3D P (H|D) = P(5 n #) = 0 %3D P(D) =D025 %3D Save For Later Submit Assig Check 2020 McGraw-Hill Education. All Rights Reserved. Terms of Use| Privacy Acc ype here to search %3D Question 10 of 10 (10 points) Question Attempt: 1 of Unlimited (If necessary, consult a list of formulas.) P(H|D) = P(D n H) = %3D P(D) = %3D P(pn #) = ] P(#|D) = 0.4 PH %3D P(5 n H) = [] P(D) = 025 P(5n F) = ] P(HD) = 0,6 %3D What is the probability that a randomly chosen voter did notn vote for Hector? Save For Check O 2020 McGraw-Hill Education. All Rights Reserved P Type here to search ip の Recently, Hector ran for president of the local school board. Of those who voted in the election, 75% had a high school diploma, and the other 25% did not. Hector got 60% of the vote of those with high school diplomas, while he got only 40% of the vote of those without high school diplomas. Let D denote the event that a randomly chosen voter (in the school board election) had a high school diploma and D denote the event that a randomly chosen voter did not have a high school diploma. Let H denote the event that a randomly chosen voter voted for Hector and H denote the event that a randomly chosen voter did not vote for Hector. Fill in the probabilities to complete the tree diagram below, and then answer the question that follows. Do not round any of your responses. (If necessary, consult a list of formulas.) P(H|D) = %3D P (D N H) = |[ U. P (D) = | %3D P(pn #) = %3D P(#|D) = 0.4 %3D P (H|D) = P(5 n #) = 0 %3D P(D) =D025 %3D Save For Later Submit Assig Check 2020 McGraw-Hill Education. All Rights Reserved. Terms of Use| Privacy Acc ype here to search %3D Question 10 of 10 (10 points) Question Attempt: 1 of Unlimited (If necessary, consult a list of formulas.) P(H|D) = P(D n H) = %3D P(D) = %3D P(pn #) = ] P(#|D) = 0.4 PH %3D P(5 n H) = [] P(D) = 025 P(5n F) = ] P(HD) = 0,6 %3D What is the probability that a randomly chosen voter did notn vote for Hector? Save For Check O 2020 McGraw-Hill Education. All Rights Reserved P Type here to search ip の