Question: Rectangle Difference There are two ways of defining rectangle difference: Largest - cover difference, which returns the difference represented by rectangles that are as large

Rectangle Difference
There are two ways of defining rectangle difference:
Largest-cover difference, which returns the difference represented by rectangles that are as large as possible, and therefore may be overlapping.
Disjoint difference, which retums rectangles that are disjoint.
Largest-Cover Difference
Given two rectangles R=(I1,I2,dots,In) and T=(J1,J2,dots,Jn), their difference R-T is the region =tildeR??tilde(T). We make the following observation: for a point to be in R and not in T, all it takes is that in one of the dimensions k, it is in Ik, but not in Jk.
Based on this idea, we construct a representation of ?barR???bar(T) as follows. We initialize the list of result rectangles to be empty. Then, we iterate over all dimensions k=1,2,dots,n, and for each dimension k, we construct rectangles with intervals I1,dots,Ik-1,Ik-Jk,Ik+1,dots,In. where Ik-Jk represents interval difference. There can be 0,1, or 2 intervals in Ik-Jk, and correspondinglys
I1,dots,Ik-1,Ik-Jk,Ik+1dots,In will consist of 0,1, or 2 rectangles; we add all such rectangles to the result list. Let's translate this idea into code.
Implementation of largest-cover difference
Fictitle Implementation of largest-cover difference
def rectangle_difference(r,t :
"'"."Computes the rectangle difference r-t, and outputs the result
as a list of rectangles." "u."
assert ten(r)=len(t), "Rectangles have different dimensions"
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 Rectangle Difference There are two ways of defining rectangle difference: Largest-cover

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