Redo the program below by reading each digit of the number to be tested
into a type char variable digit . Display each digit and form the sum of the
numeric values of the digits. Hint: The numeric value of digit is (int) digit - (int) '0'.

#include <stdio.h>

int main()

{

int n = 154368;

  

int sum = 0;

  

while(n)

{

printf("%d ",n%10);

sum = sum+n%10;

n = n/10;

}

  

if(sum%9==0)

printf("\nTrue");

else

printf("\nFalse");

return 0;

}

Answer rating: 100% (QA)

Coding include int main int n 154368 int sum ... View the full answer