Reduce to Exact

$(xy+y^2+y)dx+(x^2+3xy+2x)dy=0$

$(x{y}^2-e^{\frac{1}{x^3}})dx-x^{2}ydy=0$

$(2x^3{y}^2+4x^{2}y+2x{y}^2+x{y}^4+2y)dx+$

$2(y^3+x^{2}y+x)dy=0$