Refer to the data in the accompanying table for the heights of females. Complete parts (a)...

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Refer to the data in the accompanying table for the heights of females. Complete parts (a) through (d) below. Click the icon to view the table of height data. a. Enter the observed frequencies in the table below. Height (cm) Less than 154.85 154.85-161.75 Frequency 161.75 -168.65 Greater than 168.65 (Type whole numbers.) b. Assuming a normal distribution with mean and standard deviation given by the sample mean and standard deviation, find the probability of a randomly selected height belonging to each class. Height (cm) Less than 154.85 154.85-161.75 Probability 161.75 168.65 Greater than 168.65 (Round to four decimal places as needed.) 161.75 168.65 Greater than 168.65 c. Using the probabilities found in part (b), find the expected frequency for each category. Height (cm) Less than 154.85 154.85-161.75 Expected Frequency (Round to two decimal places as needed.) d. Use a 0.10 significance level to test the claim that the heights were randomly selected from a normally distributed population. Does the goodness-of-fit test suggest that the data are from a normally distributed population? Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. Ho: For each height class, the observed frequency is not equal to the corresponding expected frequency. H: For each height class, the observed frequency is equal to the corresponding expected frequency. B. Ho: The observed frequencies for each height class are equal to each other. H: At least one of the observed frequencies is not equal to the other observed frequencies. C. Ho: For each height class, the observed frequency is equal to the corresponding expected frequency. H: For at least one height class, the observed frequency is not equal to the corresponding expected frequency. D. Ho: For each height class, the observed frequency is equal to the corresponding expected frequency. H: For each height class, the observed frequency is not equal to the corresponding expected frequency. Identify the test statistic. x = (Round to two decimal places as needed.) Identify the P-value. P-value= (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. Ho. There is evidence at a 0.10 significance level to warrant rejection of the claim that the female heights were randomly selected from a normally distributed population. Heights 171.98 154.41 155.68 157.59 168.62 164.01 159.50 155.42 178.77 155.61 149.02 155.59 156.82 154.80 155.49 155.01 154.91 161.49 160.02 163.58 164.70 170.20 154.62 159.47 167.12 156.79 169.50 170.91 151.61 159.67 158.38 173.59 160.11 164.78 172.11 153.17 134.53 169.12 160.22 157.82 166.31 158.41 177.82 152.40 164.08 160.63 167.70 158.78 156.53 157.62 Print Done - Refer to the data in the accompanying table for the heights of females. Complete parts (a) through (d) below. Click the icon to view the table of height data. a. Enter the observed frequencies in the table below. Height (cm) Less than 154.85 154.85-161.75 Frequency 161.75 -168.65 Greater than 168.65 (Type whole numbers.) b. Assuming a normal distribution with mean and standard deviation given by the sample mean and standard deviation, find the probability of a randomly selected height belonging to each class. Height (cm) Less than 154.85 154.85-161.75 Probability 161.75 168.65 Greater than 168.65 (Round to four decimal places as needed.) 161.75 168.65 Greater than 168.65 c. Using the probabilities found in part (b), find the expected frequency for each category. Height (cm) Less than 154.85 154.85-161.75 Expected Frequency (Round to two decimal places as needed.) d. Use a 0.10 significance level to test the claim that the heights were randomly selected from a normally distributed population. Does the goodness-of-fit test suggest that the data are from a normally distributed population? Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. Ho: For each height class, the observed frequency is not equal to the corresponding expected frequency. H: For each height class, the observed frequency is equal to the corresponding expected frequency. B. Ho: The observed frequencies for each height class are equal to each other. H: At least one of the observed frequencies is not equal to the other observed frequencies. C. Ho: For each height class, the observed frequency is equal to the corresponding expected frequency. H: For at least one height class, the observed frequency is not equal to the corresponding expected frequency. D. Ho: For each height class, the observed frequency is equal to the corresponding expected frequency. H: For each height class, the observed frequency is not equal to the corresponding expected frequency. Identify the test statistic. x = (Round to two decimal places as needed.) Identify the P-value. P-value= (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. Ho. There is evidence at a 0.10 significance level to warrant rejection of the claim that the female heights were randomly selected from a normally distributed population. Heights 171.98 154.41 155.68 157.59 168.62 164.01 159.50 155.42 178.77 155.61 149.02 155.59 156.82 154.80 155.49 155.01 154.91 161.49 160.02 163.58 164.70 170.20 154.62 159.47 167.12 156.79 169.50 170.91 151.61 159.67 158.38 173.59 160.11 164.78 172.11 153.17 134.53 169.12 160.22 157.82 166.31 158.41 177.82 152.40 164.08 160.63 167.70 158.78 156.53 157.62 Print Done -