Question: Refine this code so that the code is not duplicated but still performs the same task def copy_image_to_blank_canvas(): # source image image1 = Image open(.

Refine this code so that the code is not duplicated but still performs the same task  Refine this code so that the code is not duplicated but

def copy_image_to_blank_canvas(): # source image image1 = Image" open(". png") image2 Image.open(.png") image3 Image.open(".png") # destination image canvas = Image. new("RGB", (2000,800), "white") target-x = 0 for source_x in range(image1.width): target-y = 0 for source y in range (imagel.height) # get pixels # put pixels onto target from the source color-image1.getpixel( (source-x, canvas. putpixel( (target-x, target-y source_y)) target-y), color) += 1 target_x e 1 target y for source_y in range(image2. height): for source_x in range(image2.width): color = image2.getpixel( (source_x, source-y)) # get pixels from the source canvas. putpixel( (target-x, target-y), color) # put pixels onto target target-y += 1 target-x 1 += for source- in range (inage3.width): target y for source y in range(image3.height)

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