Question: Removes the element at the specified position in this list. Shifts any subsequent elements to the left * (subtracts one from their indices). Returns the

Removes the element at the specified position in this list. Shifts any subsequent elements to the left * (subtracts one from their indices). Returns the element that was removed from the list. * * @param index the index of the element to be removed * @return the element previously at the specified position * @throws IndexOutOfBoundsException if the index is out of range */ @Override public E remove(int index) { return null; }
{@link #remove} recursive helper method. Removes the node following n if it contains the element at the specified * index. * * @param index the index of the element to be removed * @param currentIndex the index of the node parameter * @param n the node containing the element at currentIndex * @return */ private E remove(int index, int currentIndex, Node n) { return null; }
Returns a string representation of this list. This string should consist of a comma separated list of values * contained in this list, in order, surrounded by square brackets (examples: [3, 6, 7] and []). * * @return a string representation of this list */ public String toString() { return null; }
/** * {@link #toString} recursive helper method. Returns a string representation of this list, beginning with the * element in the specified node * * @param n the node containing the next element to append to the string * @return a string representation of this list, beginning with the element in the specified node */ private String toString(Node n) { return null; } 

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