Repeat ((example20.1-2)) but use a distribution coefficient K=0.50 instead of 2.0. plot the data

Slab EXAMPLE 20.1-2. Unsteady-State Diffusion in a Semi-infinite A very thick slab has a uniform concentration of solute A of c = 10 * 10-2kg mol Am Suddenly, the front face of the slab is exposed to a flowing tluld having a concentration G = 0.10 kg mol Almand a convective coefficient k = 2 x 10-7 ms. The equilibrium 860 distribution coefficient Kuc; = 2.0. Assuming that the slab is a semi-infinite solid, calculate the concentration in the solid at the surface (s 0) and x=0.01 m from the surface after = 3 * 10's. The diffusivity in the solid is Das = 4 10 ms. Solution: To use Fig. 143-3, use Table 20.1.1. 202x107 KA 10***s x 10-**) 1.095 410 For x = 0.01 m from the surface in the solid. 0.001 0.457 210 24 x 10" 13x10-) From the chart 1 - Y=0.26. Then, substituting into the equation for (1-) from Table 20.1-1 and solving 1 x 10 1-Y 0.26 G/R- 10 x 10 1x to make c2.04x10mm x 101 m) For x = 0 m (.e, at the surface of the solid), 2. De 0 From the chart, 1 - Y0.62. Solving, c = 3.48 * 10-2 This value is the same as , as shown in Fig. 20.1-3. To calculate the concentration in the liquid at the intertace, C-k - 203.48*10 -6.96 x 10 361