Repeat the previous exercise with the modified circuit shown above.

Answers:

a$)v_o(t)=\{\begin{array}{cc}10-20e^{-t}+10e^{-2t}V,& 0t0\mathrm{.}5s\\ -5+17\mathrm{.}925e^{-(t-0\mathrm{.}5)}-11\mathrm{.}375e^{-2(t-0\mathrm{.}5)}V,& t0\mathrm{.}5s\end{array}$

$v_{o1}(t)=\{\begin{array}{cc}0\mathrm{.}8e^{-2t}-0\mathrm{.}8V,& 0t0\mathrm{.}5s\\ -0\mathrm{.}91e^{-2(t-0\mathrm{.}5)}+0\mathrm{.}4V,& t0\mathrm{.}5s\end{array}$

b$)$ The op amps do not saturate.

c$)$