Question: Repeat the question above for the push instruction. Below is the syntax and the encoding. The instruction below pushes register t0 on the stack. Notice
Repeat the question above for the push instruction. Below is the syntax and the encoding. The instruction below pushes register t0 on the stack. Notice that the rs field encodes register sp and that the immediate value is equal to 4.
The stack in MIPS is a full descending stack. Therefore, in the push operation, the register is written to memory address (sp-4), then the value of (sp-4) is written to register sp.
push $t0
| Unique | Sp | T0 | 4 |
Opcode rs rt immediate
a) Give the functional form of the instruction based on the register names.
b) Give the functional form based on the instruction fields.
c) Draw the changes on the datapath diagram.
d) Give the values of the control signals.


Repeat the question above for the push instruction. Below is the syntax and the encoding. The instruction below pushes register to on the stack. Notice that the rs field encodes register sp and that the immediate value is equal to 4. The stack in MIPS is a full descending stack. Therefore, in the push operation, the register is written to memory address (sp-4), then the value of (sp-4) is written to register sp push Sto sp unique opcode immediate TS Repeat the question above for the push instruction. Below is the syntax and the encoding. The instruction below pushes register to on the stack. Notice that the rs field encodes register sp and that the immediate value is equal to 4. The stack in MIPS is a full descending stack. Therefore, in the push operation, the register is written to memory address (sp-4), then the value of (sp-4) is written to register sp push Sto sp unique opcode immediate TS
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