Replace the loading by a single resultant force, and specify the location of the force measured from point $O.$

SOLUTION

Equivalent Resultant Force:

$+uarr{F}_R=F_y$;$,-F_R=-22\mathrm{.}5-13\mathrm{.}5-15$

$F_R=51\mathrm{.}0$kNdarr

Ans.

Location of Equivalent Resultant Force:

$C+(M_R{)}_O=M_O$;$,-51\mathrm{.}0(d)=-500-22\mathrm{.}5(5)-13\mathrm{.}5(9)-15(12)$

$d=17\mathrm{.}9m$

Ans.