Replace the three horizontal forces and applied couple with an equivalent forcecouple system at $"$A$"$ by specifying the resultant force $F$ and the resultant moment $M_{\text{n}\text{e}\text{t}}.$ Note that these are vector quantities: Make sure you give magnitude and direction for both of these values. The parameters are $d_1=2m,d_2=2m,d_3=1m,d_4=3m,d_5=0\mathrm{.}3m,d_6=0\mathrm{.}3m,|F_1|=10kN,|F_2|=15kN,|F_3|=25kN,=70,$ and $|\frac{k}{1}|=30$ kNm $.$