Question: Reply as a student to Normalcdf(2.5, 4.5, 3.8, 0.46/) = 0.999 = 99.9% using my calculated mean and standard deviation from my sample results of

Reply as a student to "Normalcdf(2.5, 4.5, 3.8, 0.46/) = 0.999 = 99.9% using my calculated mean and standard deviation from my sample results of the week 4 discussion board, the probability of rolling a standard six-sided dice 9 times and having the mean ranging from 2.5 to 4.5 is 99.9% I would consider these results reasonably close, as there is only about a 7% difference

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