REPORT No$.12($DATA AND CALCULATIONS$)$ REMINDERS: All number must have units. Be generous with significant figures and

round off at the end.

Mass of KClO$3\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$

Mass of test tube $+$ contents before heating $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$

Mass of test tube $+$ contents after heating $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$

The mass loss due to heating can be attributed to the oxygen gas evolved. Mass of O$2$ evolved $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$

Convert the mass of oxygen to moles of O$2.$ Result here $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_($n$)$

The temperature of the O$2$ collected is assumed to be the same as the water bath. Temperature of wet O$2$ collected $\_\_\_\_\_\_\_\_\backslash$deg C $=\_\_\_\_\_\_\_\_$K $($T$1)$

Ambient pressure in mmHg $($read from barometer$)\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$

Pressure of water vapor from Table $12\mathrm{.}1\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$

The ambient pressure minus the pressure of water vapor gives the pressure of the dry oxygen collected under ambient conditions. Convert this into units of atmospheres.

Pressure of dry O$2\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_($P$1)$

Volume of water left in bottle $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$

Total volume of bottle $\_\_\_\_\_\_\_\_\_\_\_\_\_($measure it $-$ it$$s not exactly $500$ mL$)$

The volume of oxygen collected under ambient conditions is equal to the volume of water displaced. Convert to liters.

Volume of O$2\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_($V$1)$