$!$

Required information

In the given circuit, $V_x=5\mathrm{.}80V.$

Referring to the given circuit, determine the Norton equivalent of the circuit by first finding $V_{oc}$ and $\frac{?}{sC}($defined as flowing into the positive reference terminal of $V_{od}.($Round the final answers to three decimal places.$)$

The Norton equivalent of the circuit is $$ mA and $.$