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Required information

Solve the following problems for $x(t).$ The input $g(t)$ is a unit$-$step function.

Compare the values of $x(0^{+})$and $x(0^{-})$for the equation given below.

$7x^{}+5x=4g^{}+6g(t),x(0-)=3,g(0-)=0$

Multiple Choice

The value of $x(t)$ is $\frac{83}{35}{e}^{-5\frac{t}{7}}$ with $x(0+)x(0-).$

$$ The value of $x(t)$ is $\frac{83}{35}{e}^{-5\frac{t}{7}}$ with $x(0+)=x(0-).$Multiple Choice

The value of $x(t)$ is $\frac{83}{35}{e}^{-5\frac{t}{7}}$ with $x(0+)x(0-).$

The value of $x(t)$ is $\frac{83}{35}{e}^{-5\frac{t}{7}}$ with $x(0+)=x(0-).$

The value of $x(t)$ is $\frac{6}{5}+\frac{83}{35}{e}^{-5\frac{t}{7}}$ with $x(0+)=x(0-).$

The value of $x(t)$ is $\frac{6}{5}+\frac{83}{35}{e}^{-5\frac{t}{7}}$ with $x(0+)x(0-).$ Its not the second or third choice