$!$

Requlred Information

The allowable shearing stress is $19$ksI in the $0\mathrm{.}9($in$)$ dla. steel rod $AB$ and $7$ksIin the $1\mathrm{.}5($In$)$ dla. brass rod $BC.$ If a torque of magnitude $T_B=1\mathrm{.}7$kIp$-$In$.$ Is applied at $B,$ determine the allowable torque $T$ that can be applled at $A.$

The magnitude of the internal reaction between $A$&$B$ is$,$

$T+-271953(klp.In)$

$T+-29386(kp.In)$