Question: Resolved this using the EES Software. stales Stales P = 2MPa T,=4800e. T 2nd Ps = 0.3MP S5 = Sy Tubine Stalea Szes P =

Resolved this using the EES Software.

Resolved this using the EES Software. stales Stales P = 2MPa T,=4800e.

T 2nd Ps = 0.3MP S5 = Sy Tubine" Stalea Szes P

= 2MP stale 6 (bleeduj) 56=55 P6=0.008 MPa first turbine stales (blading)

stales Stales P = 2MPa T,=4800e. T 2nd Ps = 0.3MP S5 = Sy Tubine" Stalea Szes P = 2MP stale 6 (bleeduj) 56=55 P6=0.008 MPa first turbine stales (blading) S3=52 Ps =0.7MP4 stek? ( Condenser exit) X70 P-0.008 Men staley (exit rehooks). Pu = 0.7MR Tu=440C stales (pump) stale 2 Xizzo Piz=2MPa Sy P2 203 stale ? 1 of WH exit) stale 13 (value) Xp = 0 Pq = 0.3 MPa hiz hiz Pis = 0,3MR. - stale 10 (Pump). Pio= 8 MPa. SiO - S4 steell (CFWH exit) P. 1 = 8Mle To = 205C- of WH energy waservation in energy conservation in CF WH 2 (8) 2 s (8) (1-3-1) 3. H

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