Question: Results for this submission Entered Answer Preview Result 64 - cos(7)t [64-cos(7)*1//7 incorrect 7 64 - cos(9)t [64-cos(9)*1]/9 incorrect 9 (3/2)*(t^ 2)+9 - to +

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Results for this submission Entered Answer Preview Result 64 - cos(7)t [64-cos(7)*1//7 incorrect 7 64 - cos(9)t [64-cos(9)*1]/9 incorrect 9 (3/2)*(t^ 2)+9 - to + 9 correct At least one of the answers above is NOT correct. Find the solution r( t) of the differential equation with the given initial condition: r' (t) = (sin 7t, sin 9t, 3t), r(0) = (9, 6, 9) r (t) = 64 - cos 7t 64 - cos 9t 32+9 7 9Consider the paraboloid z z2 + y\". The plane 3z 3y + 2 3 0 cuts the paraboloid, its intersection being a curve Find "the natural\" parametrization of this curve. Hint: The curve which is cut lies above a circle in the xy-plane which you should parametrize as a function of the variable t so that the circle is traversed counterclockwise exactly once as t goes from 0 to 2*pi, and the paramterization starts at the point on the circle with largest x coordinate. Using that as your starting point, give the parametrization of the curve on the surface c(t) = Mt),z[t}] where ::(t) :| cos(t] ' y(t) = | reing | 2(t) :'. 1 | Find the angle of intersection of the plane 5x - 3y - 32 = 0 with the plane 4x + 2y + 52 = -1. Answer in radians: 1.51 and in degrees: 86.52
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