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The answer is NOT correct. $($in pounds$)$ of the moving ball numerically equals $4$ times its velocity $($in feet per second$).$

Suppose that after t seconds the ball is y feet below its rest position. Find y in terms of t $.($Note that the positive direction is down.$)$

Take as the gravitational acceleration $32$ feet per second per second.

$y=0\mathrm{.}2165(e^{-2\mathrm{.}1436t}-e^{-29\mathrm{.}8564t})$

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Incorrect

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${0\mathrm{.}2165}^{**}([e^{-{2\mathrm{.}1436}^{**}t}]-[e^{-{29\mathrm{.}8564}^{**}t}])$

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$0\mathrm{.}2165(e^{-2\mathrm{.}1430t}-e^{-29\mathrm{.}8644t})$

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