Review | Constants Scaling laws apply not just to organisms but also to entire ecosystems. (Figure...

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Review | Constants Scaling laws apply not just to organisms but also to entire ecosystems. (Figure 1) shows the number of trees in a 5 acre section of tropical forest with the trunk diameters shown on the horizontal axis. You can see that the forest structure is not random but follows a scaling law. In fact, this scaling law was shown to persist for over 30 years even though individual trees in this plot grew and died. Part A Determine the scaling law by reading the graph carefully and calculating the slope of the trend line. The number of trees scales with what power of the trunk diameter? Express your answer to one significant figure. Figure Number of trees 1000- 300- 100- 30- 10- 3 3 10 30 Trunk diameter (cm) 100 r = 1 of 1 Submit Previous Answers Request Answer ? Incorrect; Try Again; 5 attempts remaining Provide Feedback Next > Part A RNA polymerase is an enzyme that moves along strands of DNA, reads the genetic code, and creates a matching strand of mRNA (messenger RNA). RNA polymerase transcribes DNA at the rate of about 60 bp/s (base pairs per s). DNA has a length of 0.34 nm per base pair. An average gene in the human genome is about 12,000 bp in length. What is the speed in nm/s at which RNA polymerase moves along a strand of DNA? Express your answer in nanometers per second. S = ? nm/s Submit Request Answer Part B How long does it take to transcribe a gene of average length and produce one mRNA molecule? Express your answer with the appropriate units. ? t = Value Units Submit Request Answer A study of South American mammals found that the number of species in a large area of land scales as the average - 3 4th power; that mass of individuals of the species to the is, S x m 3/4, where S is the number of distinct species (not the number of individuals). Species like sloths and monkeys have masses of roughly 5 kg. Smaller mammals, such as guinea pigs and chinchillas, have masses of roughly 0.5 kg. Part A What is the expected ratio of the number of 0.5 kg species to the number of 5 kg species? S0.5/S5 = Submit Request Answer Provide Feedback ? Review | Constants Scaling laws apply not just to organisms but also to entire ecosystems. (Figure 1) shows the number of trees in a 5 acre section of tropical forest with the trunk diameters shown on the horizontal axis. You can see that the forest structure is not random but follows a scaling law. In fact, this scaling law was shown to persist for over 30 years even though individual trees in this plot grew and died. Part A Determine the scaling law by reading the graph carefully and calculating the slope of the trend line. The number of trees scales with what power of the trunk diameter? Express your answer to one significant figure. Figure Number of trees 1000- 300- 100- 30- 10- 3 3 10 30 Trunk diameter (cm) 100 r = 1 of 1 Submit Previous Answers Request Answer ? Incorrect; Try Again; 5 attempts remaining Provide Feedback Next > Part A RNA polymerase is an enzyme that moves along strands of DNA, reads the genetic code, and creates a matching strand of mRNA (messenger RNA). RNA polymerase transcribes DNA at the rate of about 60 bp/s (base pairs per s). DNA has a length of 0.34 nm per base pair. An average gene in the human genome is about 12,000 bp in length. What is the speed in nm/s at which RNA polymerase moves along a strand of DNA? Express your answer in nanometers per second. S = ? nm/s Submit Request Answer Part B How long does it take to transcribe a gene of average length and produce one mRNA molecule? Express your answer with the appropriate units. ? t = Value Units Submit Request Answer A study of South American mammals found that the number of species in a large area of land scales as the average - 3 4th power; that mass of individuals of the species to the is, S x m 3/4, where S is the number of distinct species (not the number of individuals). Species like sloths and monkeys have masses of roughly 5 kg. Smaller mammals, such as guinea pigs and chinchillas, have masses of roughly 0.5 kg. Part A What is the expected ratio of the number of 0.5 kg species to the number of 5 kg species? S0.5/S5 = Submit Request Answer Provide Feedback ?