REVIEW!! Suppose $G(x)={\displaystyle \underset{-2}{\overset{x}{}}}{t}^3*8^{t}dt.$ What $is{G}^{\text{'}}(x)?$

$G^{\text{'}}(x)={\displaystyle \underset{-2}{\overset{1}{}}}{t}^3*8^{t}dt$

$G^{\text{'}}(x)={\displaystyle \underset{-2}{\overset{x}{}}}3t^2*ln(8)8^{t}dt$

$G^{\text{'}}(x)={\displaystyle \underset{-2}{\overset{x}{}}}\frac{1}{4}{t}^4*\frac{1}{ln(8)}{8}^{t}dt$

$G^{\text{'}}(x)=3x^2*8^x+x^3*ln(8)8^x$

$G^{\text{'}}(x)=x^3*8^x$