Rewrite the C program below using Scheme. Your Scheme code should generate the same output.

#include

int func$($int a$,$ int b$)\{$

return $($a $*$ a $+$ b$)$;

$\}$

int main$($void$)\{$

int x$[]=\{1,2,3,4\}$;

int y$[]=\{3,4,9,2\}$;

int z$[4]$;

for $($int ii$=0$;ii$<4$;ii$++)\{$

z$[$ii$]=$ func$($x$[$ii$],$y$[$ii$])$;

$\}$

for $($int ii$=0$;ii$<4$;ii$++)\{$

printf$("\%$d $",$ z$[$ii$])$;

$\}$

return $0$;

$\}$

Rewrite the Scheme program below using C$.$ Your C code should generate the same output.

$($define a $10)$

$($define b $5)$

$($define c $(+$ a b$))$

$($define func

$($lambda $($c$)$

$($if $(=$ c $0)$

$\text{'}()$

$($cons c $($func $(-$ c $1))))))$

$($func a$)$

$($func c$)$