roblem #2: Suppose that the augmented matrix for a system of linear equations has been reduced by row operations to the following reduced row echelon form. Solve the system. -6 0 0 3 0 0 1 0 -3 9 0 0 00 0 1 5 4 0 0 0 0 0 (A) x1=6-3s-91 (B) x =-9+ 6s-31 (C) x =-6+3s-9t (D) no solution x2=S x3=9+31 x2=s x3=-3s+9t x4=4-5t x5=1 x4 = 5s + 4t x5=t x3=3s+91 x4=-5s+4t x5=1 (F) x1-9 *2=0 (G) x =9-6s+ 31 x2=S x3=-9 x3=-9-31 x4=-4 x4=-4+5t x5=0 x5=1 (E) x=6-3s+91 (inconsistent) x2=s -3s-9t x4--5s-4t x5=t