Rod $\backslash ($ A B $\backslash )$ is held in place by the cord $\backslash ($ A C $\backslash ).$ Knowing that $\backslash ($ c$=930\backslash$mathrm$\{$~mm$\}\backslash )$ and that the moment about $\backslash ($ B $\backslash )$ of the force exerted by the cord is $840$ N $-$m$,$ determine the tension in the cord by the three methods Indicated. Enter Intermediate step answers. Draw a separate Free Body Dlagram for each method.

a$)$ by applying the cable tension at $\backslash (\backslash$mathbf$\{$A$\}\backslash )$ perpendleular to $\backslash (\backslash$operatorname$\{$rod$\}\backslash$mathbf$\{$A B$\}\backslash )$

Angle between horizontal and rod AB

Angle between horizontal and cable AC

Angle BAC

Length of $\backslash (\backslash$operatorname$\{$rod$\}$ A B$=\backslash )$

Tac $\backslash (=\backslash )$ Tension in Cable AC$.$

Component of Tac perpendicular to $\backslash (\backslash$operatorname$\{$rod$\}$ A B$=\backslash )$

N

Moment of Cable tension about pin B $=$

Nm clockwise

b$)$ by applying the cable tension at C

Angle between horizontal and cable $\backslash ($ A C $\backslash )$

horizontal component of Tac $=$ N

Moment of Cable tension about pin B $=$

N m clockwise

c$)$ using horlzontal$(\backslash ($ x $\backslash ))$ and vertical$(\backslash ($ y $\backslash ))$ components

Use negative numbers for left or down components.

Position $\backslash ($ B $\backslash )$ to $\backslash ($ A$=\backslash$quad $\backslash$mathrm$\{$ml$\}-\backslash$quad $\backslash$mathrm$\{$mJ$\}\backslash )$

Tac components $\backslash (=\backslash )$

$\backslash (1+\backslash$quad J $\backslash )$

Moment of Cable tension about pin $\backslash (\backslash$mathrm$\{$B$\}=\backslash )$

$|$N m clockwise