Question: r(t) = esti + est cos t j + est sin tk r'(t) = 3e3ti + (3e3t cost - e3t sin thi + (3e3t sin


r(t) = esti + est cos t j + est sin tk r'(t) = 3e3ti + (3e3t cost - e3t sin thi + (3e3t sin t + e3t cos t) k = e3t[3i + (3 cos(t) - sin t)j + (3 sin t + cos t)k] | |r' (t) |1 = e3t 9 + 9 cost) - 6 cost sin t + (sint) )+ 9 ( sint) + 6 sint cost+ (cost))| 1/2 = e 3t 19 71/2
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