Question: S n = A n ' B n ' C n + A n ' B n C n ' + A n B n

Sn=An'Bn'Cn+An'BnCn'+AnBn'Cn'+AnBnCn
Cn+1=AnBn+AnCn+BnCn
Questions:
Count how many 2-input gates are required to implement the minimum SOP of Sn(above), including 3 NOT gates.
Count how many 2-input gates are required to implement the minimum SOP of Cn+1(above).
If you built both circuits, how many gates would you need for one full adder? What about four full adders?
Prove that Sn=Ano+Bno+Cn. Show your work. How many 2-input gates are required to implement this?
Prove that Cn+1=AnBn+Cn(Ano+Bn). Show your work. (Hint: try expanding An+BnAn'Bn+AnBn'+AnBn). How many 2-input gates are required to implement this?
Can any gates be shared between the new expressions for Sn and Cn+1? If they share, how many 2-input gates are required to implement one full adder using these circuits?
I just need 5 and 4
S n = A n ' B n ' C n + A n ' B n C n ' + A n B n

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