sames

Partial fraction decompesition can now be used to write $\frac{?}{{?}_y},$ such that all terms Rave linear denominators, which is required to move forward.

$\frac{2s-11}{(s-6)(s+4)}=\frac{A}{s-6}+\frac{B}{s+4}$

$2s-11=A(s+4)+B(s-6)$

Now, solve for A and $B$ by utiaing the real roots of the denominatos, $6$ and $-4.$ Doing so gives the following results.

$\{\begin{array}{c}\text{:}A=\frac{10}{B}=\frac{10}{B}\end{array}$

Therefore, we have the following.

$\frac{2s-11}{(s-6)(s+4)}=\frac{4}{s-6}+\frac{8}{s+4}$

$=\frac{(\frac{1}{10})}{s-6}+\frac{1-\frac{10}{s+4}}{s+4}$

$$

SKIP $($YOU CANNOT COME BACK$)$