Question: Sample Problem. An ideal engine has an efficiency of 28 percent when the temperature of its hot reservoir is 120 C. What is the temperature

Sample Problem. An ideal engine has an efficiency of 28 percent when the temperature of its hot reservoir is 120" C. What is the temperature of its cold reservoir? How much work did this engine do for an input energy of 5500 J? Given: Efficiency- 28% THr=120" C + 273 =393 K Solution: Substituting the given values in the equation for ideal efficiency, 28% - 393 K -T, x 100 393 K To= 393 K - (28 K) (393 K) / 100 = 282.96 K = 283 K Using efficiency = work X 100 Input energy 28% W X 100 5500 J W= 1540 J

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