Score: $\frac{0}{1}$

Penalty: none

Question

$(6)$

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Given: AECF is a parallelogram, $\frac{?}{\text{b}\text{a}\text{r}}(EB)$~$\frac{?}{b}=ar(FD)$ and $\frac{?}{{?}_B}$~$\frac{?}{{?}_D}=.$

Prove: AECF is a rhombus.

Step

Statement

Reason

AECF is a parallelogram

$1$

$\frac{?}{\text{b}\text{a}\text{r}}(EB)$~$\frac{?}{b}=ar(FD)$

$\frac{?}{{?}_B}$~$\frac{?}{{?}_D}=$

$2$

$\frac{?}{{?}_{A}EC}$~$\frac{?}{{?}_A}=FC$

Given

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