Scores

eText

Study Area

Document Sharing

User Settings

$1\mathrm{.}4{10}^4\frac{N}{m^2}0\mathrm{.}40\frac{m}{s}in$ a horizontal artery $of$ radius $1\mathrm{.}0cm.$ The average pressure $is1\mathrm{.}4{10}^4\frac{N}{m^2}$ above atmospheric pressure $(the$ gauge pressure$).$