second bulb + Vbat A The voltage across the battery Vis 8.00 V. A connecting wire runs from the battery to the first bulb. A second connecting wire runs from the first bulb to the second, and a third wire from the second bulb back to the battery. Because the resistance in these connecting wires is very small, by Ohm's law, the voltage drop across the connecting wires is very small. Therefore, we typically approximate the voltage across connecting wires as zero. This means we only have to worry about the voltages across the light bulbs. Suppose we measure the voltage magnitude across the first bulb to be 4.50 V. What then must be the magnitude of the voltage across the second bulb? (Enter your answer in volts. Enter a magnitude only-don't worry about the sign.) v We can then apply Ohm's law to find the current. Ohm's law relates the current through a resistor to the voltage across the resistor and the resistance, or R' where I is the current, V is the voltage, and R is the resistance. If the resistance of the second bulb in the circuit is 7.00 0, what is the current (in A) through the resistor? A What do we now know about the current in the first bulb? O It is greater than it is in the second bulb. O It is less than it is in the second bulb. It is the same as it is in the second bulb