Section 11.1 and section 11.2 part 1

Q1

Solve the triangle, if possible. Determine the number of possible solutions. A=T77 a=127 b=91 Select the comect choice below and fill in the answer boxes within the choice. (Round to the nearest tenth as needed.) () A. Thereis only 1 possible solution for the triangle. The measurements for the remaining angles A and C and side c are as follows. mLB= mZLC=| The length of side c= (Z) B. There are 2 possible solutions for the triangle. The measurements for the solution with the longer side c are as follows. mLB= mZLC=| The length of side c= The measurements for the solution with the shorter side are as follows. mLB= mZLC=| The length of side c= () C. There are no possible solutions for the triangle. Solve the triangle, if possible. Determine the number of possible solutions. A=388" a=35 c=116 Select the comect choice below and fill in the answer boxes within the choice. () A. There are 2 possible solutions for the triangle. The measurements for the solution with the longer side b are as follows. msLB= mZC= The length of side b= (Round to the nearest (Round to the nearest (Round to the nearest tenth tenth as needed ) tenth as needed.) as needed.) The measurements for the solution with the shorter side b are as follows. mB=| mLC= The length of side b= (Round to the nearest (Round to the nearest (Round to the nearest tenth tenth as needed.) tenth as needed.) as needed.) () B. There is only 1 possible solution for the triangle. The measurements for the remaining angles B and C and side b are as follows. mB= mLC= | The length of side b= (Round to the nearest (Round to the nearest (Round to the nearest tenth tenth as needed.) tenth as needed.) as needed.) i) C. There are no possible solutions for the triangle