$($Section $4\mathrm{.}4)$ Suppose

${\displaystyle \underset{-8}{\overset{-0\mathrm{.}5}{}}}f(x)dx=10,{\displaystyle \underset{-8}{\overset{-5\mathrm{.}5}{}}}f(x)dx=1,{\displaystyle \underset{-3}{\overset{-0\mathrm{.}5}{}}}f(x)dx=3.$

${\displaystyle \underset{-5\mathrm{.}5}{\overset{-3}{}}}f(x)dx=$

${\displaystyle \underset{-3}{\overset{-5\mathrm{.}5}{}}}(10f(x)-1)dx=$