Section

4.4&4-97

\ A geosynchronous satellite orbits Earth at a distance of 42,250.0

km

and has a period of 1 day. What is the centripetal acceleration of the satellite?\

0.446(m)/(s^(2))

\

0.114(m)/(s^(2))

\

0.223(m)/(s^(2))

\

2.23(m)/(s^(2))

\

1.15(m)/(s^(2))

A geosynchronous satellite orbits Earth at a distance of 42,250.0 km and has a period of 1 day. What is the centripetal acceleration of the satellite? 0.446m/s2 0.114m/s2 0.223m/s2 2.23m/s2 1.15m/s2 A geosynchronous satellite orbits Earth at a distance of 42,250.0 km and has a period of 1 day. What is the centripetal acceleration of the satellite? 0.446m/s2 0.114m/s2 0.223m/s2 2.23m/s2 1.15m/s2